Molar Mass of Aluminum Acetate (Al(C2H3O2)3)
Molar Mass of Aluminum Acetate makes it easier to move between measured grams and moles in classroom precipitation problems. Molar Mass of Al(C₂H₃O₂)₃ is 204.11 g/mol, based on 4 element types, with O contributing the largest share.
For fast checks, use the calculate molar mass, verify element values in the periodic table with molar mass, or explore more molar mass calculations.
Molar Mass of Aluminum Acetate is:
204.11 g/mol
Molar Mass of Al(C₂H₃O₂)₃ equals 204.11 g/mol, so 204.11 grams is one mole.
Element Breakdown Table
| Element | Count | Atomic mass | Calculation | Contribution |
|---|---|---|---|---|
| Aluminum (Al) | 1 | 26.98 | 1 x 26.98 | 26.98 g/mol |
| Carbon (C) | 6 | 12.01 | 6 x 12.01 | 72.07 g/mol |
| Hydrogen (H) | 9 | 1.01 | 9 x 1.01 | 9.07 g/mol |
| Oxygen (O) | 6 | 16.00 | 6 x 16.00 | 95.99 g/mol |
Final molar mass 26.980 + 72.070 + 9.070 + 95.990 | 204.11 g/mol | |||
Computing Molar Mass of Aluminum Acetate Step by Step
Molar Mass of Aluminum Acetate: Step-by-Step Calculation
1. Identify Element Counts
Read Al(C2H3O2)3 and list how many atoms of each element are present:
- 1 atom of Aluminum (Al)
- 6 atoms of Carbon (C)
- 9 atoms of Hydrogen (H)
- 6 atoms of Oxygen (O)
2. Determine Atomic Masses
Look up each element mass from the periodic table:
- Aluminum (Al) ~= 26.982 g/mol
- Carbon (C) ~= 12.011 g/mol
- Hydrogen (H) ~= 1.008 g/mol
- Oxygen (O) ~= 15.999 g/mol
3. Multiply Atomic Mass by Quantity
Multiply atom count by atomic mass for each element:
- Aluminum (Al): 1 x 26.982 = 26.980 g/mol
- Carbon (C): 6 x 12.011 = 72.070 g/mol
- Hydrogen (H): 9 x 1.008 = 9.070 g/mol
- Oxygen (O): 6 x 15.999 = 95.990 g/mol
4. Sum Total Molar Mass
Add all contributions to get the final molar mass in g/mol.
Molar Mass = (1 x 26.982 + 6 x 12.011 + 9 x 1.008 + 6 x 15.999)
Molar Mass = 26.980 + 72.070 + 9.070 + 95.990
Molar Mass = 204.110 g/mol
Final rounded value shown on this page: 204.11 g/mol.
Visual Calculation Chart
| Element | Count | Mass | Count x mass | Contribution |
|---|---|---|---|---|
| Aluminum (Al) | 1 | 26.982 | 1 x 26.982 | = 26.980 |
| Carbon (C) | 6 | 12.011 | 6 x 12.011 | = 72.070 |
| Hydrogen (H) | 9 | 1.008 | 9 x 1.008 | = 9.070 |
| Oxygen (O) | 6 | 15.999 | 6 x 15.999 | = 95.990 |
Final molar mass 26.980 + 72.070 + 9.070 + 95.990 | = 204.110 | |||
Easy Way to Remember
Easy way to remember Molar Mass of Aluminum Acetate
- Molar Mass of Aluminum Acetate: count atoms, multiply masses, and add totals.
- Write each element in a table so you do not miss subscripts.
- Keep 2-3 decimals during steps, then round only at the end.
Sample Reactions
| Type | Reaction |
|---|---|
| Double displacement | AgNO₃ + NaCl → AgCl + NaNO₃ |
| Acid-salt reaction | Na₂CO₃ + ₂HCl → ₂NaCl + H₂O + CO₂ |
Do You Know?
– Aluminum Acetate contains 4 element types: Al, C, H, O.
– O contributes the largest share of this compound's total molar mass.
– In Al(C₂H₃O₂)₃, H appears with the highest atom count.
– Its molar mass is 204.11 g/mol, which is used directly in gram-to-mole conversions.
– A common reaction for Aluminum Acetate is double displacement (AgNO₃ + NaCl → AgCl + NaNO₃).
For more examples in the same format, browse the related formulas on molar mass calculations.
Why This Compound Matters
Aluminum Acetate appears in ionic-reaction practice and precipitation examples in school chemistry.
Its molar mass helps students move quickly between grams, moles, and concentration problems.
Similar calculations can be compared with Aluminum Hydrogen Carbonate (Al(HCO3)3) and Sodium Bicarbonate (NaHCO3).
Where This Is Used
- Competitive exams and school chemistry tests.
- Lab work when preparing measured solutions.
- Real-world manufacturing and quality checks.
Common Mistakes When Calculating This
- Skipping subscripts in Al(C₂H₃O₂)₃ and miscounting atoms.
- Forgetting that parentheses in Al(C₂H₃O₂)₃ multiply the entire grouped part.
- Mixing up O element contribution with total molar mass.
- Reporting a value without units; final answer should be in g/mol for Aluminum Acetate.
Quick Revision
Formula: Al(C2H3O2)3
Molar Mass: 204.11 g/mol
Key takeaway: count atoms accurately, multiply by atomic masses, and sum only at the end.
Formula Explanation
Al(C2H3O2)3 contains Aluminum (Al) (1), Carbon (C) (6), Hydrogen (H) (9), Oxygen (O) (6). Add each element contribution to get total molar mass.
FAQ
Conclusion
Molar Mass of Aluminum Acetate and Molar Mass of Al(C₂H₃O₂)₃ are now easy to revise with this structured page. You can use this method in exams, lab reports, and daily chemistry practice.