Molar Mass of Iron(III) Oxide (Fe2O3)
Molar Mass of Iron(III) Oxide is commonly used in ionic-equation practice and concentration calculations for salt solutions. Molar Mass of Fe₂O₃ is 159.69 g/mol, based on 2 element types, with Fe contributing the largest share.
For fast checks, use the calculate molar mass, verify element values in the periodic table with molar mass, or explore more molar mass calculations.
Molar Mass of Iron(III) Oxide is:
159.69 g/mol
Molar Mass of Fe₂O₃ equals 159.69 g/mol, so 159.69 grams is one mole.
Element Breakdown Table
| Element | Count | Atomic mass | Calculation | Contribution |
|---|---|---|---|---|
| Iron (Fe) | 2 | 55.84 | 2 x 55.84 | 111.69 g/mol |
| Oxygen (O) | 3 | 16.00 | 3 x 16.00 | 48.00 g/mol |
Final molar mass 111.690 + 48.000 | 159.69 g/mol | |||
Computing Molar Mass of Iron(III) Oxide Step by Step
Molar Mass of Iron(III) Oxide: Step-by-Step Calculation
1. Identify Element Counts
Read Fe2O3 and list how many atoms of each element are present:
- 2 atoms of Iron (Fe)
- 3 atoms of Oxygen (O)
2. Determine Atomic Masses
Look up each element mass from the periodic table:
- Iron (Fe) ~= 55.845 g/mol
- Oxygen (O) ~= 15.999 g/mol
3. Multiply Atomic Mass by Quantity
Multiply atom count by atomic mass for each element:
- Iron (Fe): 2 x 55.845 = 111.690 g/mol
- Oxygen (O): 3 x 15.999 = 48.000 g/mol
4. Sum Total Molar Mass
Add all contributions to get the final molar mass in g/mol.
Molar Mass = (2 x 55.845 + 3 x 15.999)
Molar Mass = 111.690 + 48.000
Molar Mass = 159.690 g/mol
Final rounded value shown on this page: 159.69 g/mol.
Visual Calculation Chart
| Element | Count | Mass | Count x mass | Contribution |
|---|---|---|---|---|
| Iron (Fe) | 2 | 55.845 | 2 x 55.845 | = 111.690 |
| Oxygen (O) | 3 | 15.999 | 3 x 15.999 | = 48.000 |
Final molar mass 111.690 + 48.000 | = 159.690 | |||
Easy Way to Remember
Easy way to remember Molar Mass of Iron(III) Oxide
- Molar Mass of Iron(III) Oxide: count atoms, multiply masses, and add totals.
- Write each element in a table so you do not miss subscripts.
- Keep 2-3 decimals during steps, then round only at the end.
Sample Reactions
| Type | Reaction |
|---|---|
| Double displacement | AgNO₃ + NaCl → AgCl + NaNO₃ |
| Acid-salt reaction | Na₂CO₃ + ₂HCl → ₂NaCl + H₂O + CO₂ |
Do You Know?
– Iron(III) Oxide contains 2 element types: Fe, O.
– Fe contributes the largest share of this compound's total molar mass.
– In Fe₂O₃, O appears with the highest atom count.
– Its molar mass is 159.69 g/mol, which is used directly in gram-to-mole conversions.
– A common reaction for Iron(III) Oxide is double displacement (AgNO₃ + NaCl → AgCl + NaNO₃).
Why This Compound Matters
Iron(III) Oxide appears in ionic-reaction practice and precipitation examples in school chemistry.
Its molar mass helps students move quickly between grams, moles, and concentration problems.
Similar calculations can be compared with Iron(II) Nitrate (Fe(NO3)2) and Iron(II) Nitrite (Fe(NO2)2).
Where This Is Used
- Competitive exams and school chemistry tests.
- Lab work when preparing measured solutions.
- Real-world manufacturing and quality checks.
Whenever you need lab-ready totals in those settings, molar mass page stays handy for cross-checking.
Common Mistakes When Calculating This
- Skipping subscripts in Fe₂O₃ and miscounting atoms.
- Rounding atomic masses too early before finishing all multiplication steps.
- Mixing up Fe element contribution with total molar mass.
- Reporting a value without units; final answer should be in g/mol for Iron(III) Oxide.
Quick Revision
Formula: Fe2O3
Molar Mass: 159.69 g/mol
Key takeaway: count atoms accurately, multiply by atomic masses, and sum only at the end.
Formula Explanation
Fe2O3 contains Iron (Fe) (2), Oxygen (O) (3). Add each element contribution to get total molar mass.
FAQ
Conclusion
Molar Mass of Iron(III) Oxide and Molar Mass of Fe₂O₃ are now easy to revise with this structured page. You can use this method in exams, lab reports, and daily chemistry practice.