Molar Mass of Tetradecane (C14H30)
Molar Mass of Tetradecane is helpful for yield calculations and formula checks in carbon-chain reaction questions. Molar Mass of C₁₄H₃₀ is 198.39 g/mol, based on 2 element types, with C contributing the largest share.
For fast checks, use the molar mass calculator, verify element values in the periodic table, or explore more molar mass.
Molar Mass of Tetradecane is:
198.39 g/mol
Molar Mass of C₁₄H₃₀ equals 198.39 g/mol, so 198.39 grams is one mole.
Element Breakdown Table
| Element | Count | Atomic mass | Calculation | Contribution |
|---|---|---|---|---|
| Carbon (C) | 14 | 12.01 | 14 x 12.01 | 168.15 g/mol |
| Hydrogen (H) | 30 | 1.01 | 30 x 1.01 | 30.24 g/mol |
Final molar mass 168.150 + 30.240 | 198.39 g/mol | |||
Computing Molar Mass of Tetradecane Step by Step
Molar Mass of Tetradecane: Step-by-Step Calculation
1. Identify Element Counts
Read C14H30 and list how many atoms of each element are present:
- 14 atoms of Carbon (C)
- 30 atoms of Hydrogen (H)
2. Determine Atomic Masses
Look up each element mass from the periodic table:
- Carbon (C) ~= 12.011 g/mol
- Hydrogen (H) ~= 1.008 g/mol
3. Multiply Atomic Mass by Quantity
Multiply atom count by atomic mass for each element:
- Carbon (C): 14 x 12.011 = 168.150 g/mol
- Hydrogen (H): 30 x 1.008 = 30.240 g/mol
4. Sum Total Molar Mass
Add all contributions to get the final molar mass in g/mol.
Molar Mass = (14 x 12.011 + 30 x 1.008)
Molar Mass = 168.150 + 30.240
Molar Mass = 198.390 g/mol
Final rounded value shown on this page: 198.39 g/mol.
Visual Calculation Chart
| Element | Count | Mass | Count x mass | Contribution |
|---|---|---|---|---|
| Carbon (C) | 14 | 12.011 | 14 x 12.011 | = 168.150 |
| Hydrogen (H) | 30 | 1.008 | 30 x 1.008 | = 30.240 |
Final molar mass 168.150 + 30.240 | = 198.390 | |||
Easy Way to Remember
Easy way to remember Molar Mass of Tetradecane
- Molar Mass of Tetradecane: count atoms, multiply masses, and add totals.
- Write each element in a table so you do not miss subscripts.
- Keep 2-3 decimals during steps, then round only at the end.
Sample Reactions
| Type | Reaction |
|---|---|
| Combustion | ₂C₁₄H₃₀ + ₄₃O₂ → ₂₈CO₂ + ₃₀H₂O |
| Hydrogenation | C₁₄H₃₀ + H₂ → C₁₄H₃₂ |
Do You Know?
– Tetradecane contains 2 element types: C, H.
– C contributes the largest share of this compound's total molar mass.
– In C₁₄H₃₀, H appears with the highest atom count.
– Its molar mass is 198.39 g/mol, which is used directly in gram-to-mole conversions.
– A common reaction for Tetradecane is combustion (₂C₁₄H₃₀ + ₄₃O₂ → ₂₈CO₂ + ₃₀H₂O).
For more examples in the same format, browse the related formulas on molar mass.
Why This Compound Matters
Tetradecane matters in organic chemistry, especially for fuel, solvent, or carbon-chain analysis.
Its formula pattern helps students practice molecular composition and yield calculation methods.
Similar calculations can be compared with Benzene (C6H6) and Toluene (C7H8).
Where This Is Used
- Competitive exams and school chemistry tests.
- Lab work when preparing measured solutions.
- Real-world manufacturing and quality checks.
Common Mistakes When Calculating This
- Skipping subscripts in C₁₄H₃₀ and miscounting atoms.
- Rounding atomic masses too early before finishing all multiplication steps.
- Mixing up C element contribution with total molar mass.
- Reporting a value without units; final answer should be in g/mol for Tetradecane.
Quick Revision
Formula: C14H30
Molar Mass: 198.39 g/mol
Key takeaway: count atoms accurately, multiply by atomic masses, and sum only at the end.
Formula Explanation
C14H30 contains Carbon (C) (14), Hydrogen (H) (30). Add each element contribution to get total molar mass.
FAQ
Conclusion
Molar Mass of Tetradecane and Molar Mass of C₁₄H₃₀ are now easy to revise with this structured page. You can use this method in exams, lab reports, and daily chemistry practice.