Molar Mass of Undecane (C11H24)
Molar Mass of Undecane is helpful for yield calculations and formula checks in carbon-chain reaction questions. Molar Mass of C₁₁H₂₄ is 156.31 g/mol, based on 2 element types, with C contributing the largest share.
For fast checks, use the molar mass calculator, verify element values in the periodic table, or explore more molar mass.
Molar Mass of Undecane is:
156.31 g/mol
Molar Mass of C₁₁H₂₄ equals 156.31 g/mol, so 156.31 grams is one mole.
Element Breakdown Table
| Element | Count | Atomic mass | Calculation | Contribution |
|---|---|---|---|---|
| Carbon (C) | 11 | 12.01 | 11 x 12.01 | 132.12 g/mol |
| Hydrogen (H) | 24 | 1.01 | 24 x 1.01 | 24.19 g/mol |
Final molar mass 132.120 + 24.190 | 156.31 g/mol | |||
Computing Molar Mass of Undecane Step by Step
Molar Mass of Undecane: Step-by-Step Calculation
1. Identify Element Counts
Read C11H24 and list how many atoms of each element are present:
- 11 atoms of Carbon (C)
- 24 atoms of Hydrogen (H)
2. Determine Atomic Masses
Look up each element mass from the periodic table:
- Carbon (C) ~= 12.011 g/mol
- Hydrogen (H) ~= 1.008 g/mol
3. Multiply Atomic Mass by Quantity
Multiply atom count by atomic mass for each element:
- Carbon (C): 11 x 12.011 = 132.120 g/mol
- Hydrogen (H): 24 x 1.008 = 24.190 g/mol
4. Sum Total Molar Mass
Add all contributions to get the final molar mass in g/mol.
Molar Mass = (11 x 12.011 + 24 x 1.008)
Molar Mass = 132.120 + 24.190
Molar Mass = 156.310 g/mol
Final rounded value shown on this page: 156.31 g/mol.
Visual Calculation Chart
| Element | Count | Mass | Count x mass | Contribution |
|---|---|---|---|---|
| Carbon (C) | 11 | 12.011 | 11 x 12.011 | = 132.120 |
| Hydrogen (H) | 24 | 1.008 | 24 x 1.008 | = 24.190 |
Final molar mass 132.120 + 24.190 | = 156.310 | |||
When you move to another formula, molar mass guide gives you the same step-by-step method for quick revision.
Easy Way to Remember
Easy way to remember Molar Mass of Undecane
- Molar Mass of Undecane: count atoms, multiply masses, and add totals.
- Write each element in a table so you do not miss subscripts.
- Keep 2-3 decimals during steps, then round only at the end.
Sample Reactions
| Type | Reaction |
|---|---|
| Combustion | C₁₁H₂₄ + ₁₇O₂ → ₁₁CO₂ + ₁₂H₂O |
| Hydrogenation | C₁₁H₂₄ + H₂ → C₁₁H₂₆ |
Do You Know?
– Undecane contains 2 element types: C, H.
– C contributes the largest share of this compound's total molar mass.
– In C₁₁H₂₄, H appears with the highest atom count.
– Its molar mass is 156.31 g/mol, which is used directly in gram-to-mole conversions.
– A common reaction for Undecane is combustion (C₁₁H₂₄ + ₁₇O₂ → ₁₁CO₂ + ₁₂H₂O).
Why This Compound Matters
Undecane matters in organic chemistry, especially for fuel, solvent, or carbon-chain analysis.
Its formula pattern helps students practice molecular composition and yield calculation methods.
Similar calculations can be compared with Benzene (C6H6) and Toluene (C7H8).
Where This Is Used
- Competitive exams and school chemistry tests.
- Lab work when preparing measured solutions.
- Real-world manufacturing and quality checks.
Common Mistakes When Calculating This
- Skipping subscripts in C₁₁H₂₄ and miscounting atoms.
- Rounding atomic masses too early before finishing all multiplication steps.
- Mixing up C element contribution with total molar mass.
- Reporting a value without units; final answer should be in g/mol for Undecane.
Quick Revision
Formula: C11H24
Molar Mass: 156.31 g/mol
Key takeaway: count atoms accurately, multiply by atomic masses, and sum only at the end.
Formula Explanation
C11H24 contains Carbon (C) (11), Hydrogen (H) (24). Add each element contribution to get total molar mass.
FAQ
Conclusion
Molar Mass of Undecane and Molar Mass of C₁₁H₂₄ are now easy to revise with this structured page. You can use this method in exams, lab reports, and daily chemistry practice.