Molar Mass of Barium Bromide (BaBr2)
Molar Mass of Barium Bromide is a key number in salt-related stoichiometry, especially when balancing reactants and products. Molar Mass of BaBr₂ is 297.13 g/mol, based on 2 element types, with Br contributing the largest share.
For fast checks, use the calculate molar mass, verify element values in the periodic table with molar mass, or explore more molar mass calculations.
Molar Mass of Barium Bromide is:
297.13 g/mol
Molar Mass of BaBr₂ equals 297.13 g/mol, so 297.13 grams is one mole.
Element Breakdown Table
| Element | Count | Atomic mass | Calculation | Contribution |
|---|---|---|---|---|
| Barium (Ba) | 1 | 137.33 | 1 x 137.33 | 137.33 g/mol |
| Bromine (Br) | 2 | 79.90 | 2 x 79.90 | 159.81 g/mol |
Final molar mass 137.330 + 159.810 | 297.13 g/mol | |||
Computing Molar Mass of Barium Bromide Step by Step
Molar Mass of Barium Bromide: Step-by-Step Calculation
1. Identify Element Counts
Read BaBr2 and list how many atoms of each element are present:
- 1 atom of Barium (Ba)
- 2 atoms of Bromine (Br)
2. Determine Atomic Masses
Look up each element mass from the periodic table:
- Barium (Ba) ~= 137.327 g/mol
- Bromine (Br) ~= 79.904 g/mol
3. Multiply Atomic Mass by Quantity
Multiply atom count by atomic mass for each element:
- Barium (Ba): 1 x 137.327 = 137.330 g/mol
- Bromine (Br): 2 x 79.904 = 159.810 g/mol
4. Sum Total Molar Mass
Add all contributions to get the final molar mass in g/mol.
Molar Mass = (1 x 137.327 + 2 x 79.904)
Molar Mass = 137.330 + 159.810
Molar Mass = 297.130 g/mol
Final rounded value shown on this page: 297.13 g/mol.
Visual Calculation Chart
| Element | Count | Mass | Count x mass | Contribution |
|---|---|---|---|---|
| Barium (Ba) | 1 | 137.327 | 1 x 137.327 | = 137.330 |
| Bromine (Br) | 2 | 79.904 | 2 x 79.904 | = 159.810 |
Final molar mass 137.330 + 159.810 | = 297.130 | |||
Easy Way to Remember
Easy way to remember Molar Mass of Barium Bromide
- Molar Mass of Barium Bromide: count atoms, multiply masses, and add totals.
- Write each element in a table so you do not miss subscripts.
- Keep 2-3 decimals during steps, then round only at the end.
Sample Reactions
| Type | Reaction |
|---|---|
| Double displacement | AgNO₃ + NaCl → AgCl + NaNO₃ |
| Acid-salt reaction | Na₂CO₃ + ₂HCl → ₂NaCl + H₂O + CO₂ |
Do You Know?
– Barium Bromide contains 2 element types: Ba, Br.
– Br contributes the largest share of this compound's total molar mass.
– In BaBr₂, Br appears with the highest atom count.
– Its molar mass is 297.13 g/mol, which is used directly in gram-to-mole conversions.
– A common reaction for Barium Bromide is double displacement (AgNO₃ + NaCl → AgCl + NaNO₃).
Why This Compound Matters
Barium Bromide appears in ionic-reaction practice and precipitation examples in school chemistry.
Its molar mass helps students move quickly between grams, moles, and concentration problems.
Similar calculations can be compared with Sodium Bromide (NaBr) and Potassium Bromide (KBr).
Where This Is Used
- Competitive exams and school chemistry tests.
- Lab work when preparing measured solutions.
- Real-world manufacturing and quality checks.
Common Mistakes When Calculating This
- Skipping subscripts in BaBr₂ and miscounting atoms.
- Rounding atomic masses too early before finishing all multiplication steps.
- Mixing up Br element contribution with total molar mass.
- Reporting a value without units; final answer should be in g/mol for Barium Bromide.
Spot a slip early by comparing your work with molar mass before you hand in a final value.
Quick Revision
Formula: BaBr2
Molar Mass: 297.13 g/mol
Key takeaway: count atoms accurately, multiply by atomic masses, and sum only at the end.
Formula Explanation
BaBr2 contains Barium (Ba) (1), Bromine (Br) (2). Add each element contribution to get total molar mass.
FAQ
Conclusion
Molar Mass of Barium Bromide and Molar Mass of BaBr₂ are now easy to revise with this structured page. You can use this method in exams, lab reports, and daily chemistry practice.