Molar Mass of Barium Hydroxide (Ba(OH)2)
Molar Mass of Barium Hydroxide helps students set up base-solution quantities correctly before reaction and dilution steps. Molar Mass of Ba(OH)₂ is 171.34 g/mol, based on 3 element types, with Ba contributing the largest share.
For fast checks, use the calculate molar mass, verify element values in the periodic table with molar mass, or explore more molar mass page.
Molar Mass of Barium Hydroxide is:
171.34 g/mol
Molar Mass of Ba(OH)₂ equals 171.34 g/mol, so 171.34 grams is one mole.
Element Breakdown Table
| Element | Count | Atomic mass | Calculation | Contribution |
|---|---|---|---|---|
| Barium (Ba) | 1 | 137.33 | 1 x 137.33 | 137.33 g/mol |
| Oxygen (O) | 2 | 16.00 | 2 x 16.00 | 32.00 g/mol |
| Hydrogen (H) | 2 | 1.01 | 2 x 1.01 | 2.02 g/mol |
Final molar mass 137.330 + 32.000 + 2.020 | 171.34 g/mol | |||
Computing Molar Mass of Barium Hydroxide Step by Step
Molar Mass of Barium Hydroxide: Step-by-Step Calculation
1. Identify Element Counts
Read Ba(OH)2 and list how many atoms of each element are present:
- 1 atom of Barium (Ba)
- 2 atoms of Oxygen (O)
- 2 atoms of Hydrogen (H)
2. Determine Atomic Masses
Look up each element mass from the periodic table:
- Barium (Ba) ~= 137.327 g/mol
- Oxygen (O) ~= 15.999 g/mol
- Hydrogen (H) ~= 1.008 g/mol
3. Multiply Atomic Mass by Quantity
Multiply atom count by atomic mass for each element:
- Barium (Ba): 1 x 137.327 = 137.330 g/mol
- Oxygen (O): 2 x 15.999 = 32.000 g/mol
- Hydrogen (H): 2 x 1.008 = 2.020 g/mol
4. Sum Total Molar Mass
Add all contributions to get the final molar mass in g/mol.
Molar Mass = (1 x 137.327 + 2 x 15.999 + 2 x 1.008)
Molar Mass = 137.330 + 32.000 + 2.020
Molar Mass = 171.340 g/mol
Final rounded value shown on this page: 171.34 g/mol.
Visual Calculation Chart
| Element | Count | Mass | Count x mass | Contribution |
|---|---|---|---|---|
| Barium (Ba) | 1 | 137.327 | 1 x 137.327 | = 137.330 |
| Oxygen (O) | 2 | 15.999 | 2 x 15.999 | = 32.000 |
| Hydrogen (H) | 2 | 1.008 | 2 x 1.008 | = 2.020 |
Final molar mass 137.330 + 32.000 + 2.020 | = 171.340 | |||
Easy Way to Remember
Easy way to remember Molar Mass of Barium Hydroxide
- Molar Mass of Barium Hydroxide: count atoms, multiply masses, and add totals.
- Write each element in a table so you do not miss subscripts.
- Keep 2-3 decimals during steps, then round only at the end.
Sample Reactions
| Type | Reaction |
|---|---|
| Neutralization | NaOH + HCl → NaCl + H₂O |
| Acidic oxide absorption | ₂NaOH + CO₂ → Na₂CO₃ + H₂O |
Do You Know?
– Barium Hydroxide contains 3 element types: Ba, O, H.
– Ba contributes the largest share of this compound's total molar mass.
– In Ba(OH)₂, O appears with the highest atom count.
– Its molar mass is 171.34 g/mol, which is used directly in gram-to-mole conversions.
– A common reaction for Barium Hydroxide is neutralization (NaOH + HCl → NaCl + H₂O).
Why This Compound Matters
Barium Hydroxide is used when studying neutralization, pH control, and measured base preparation.
H make it a common classroom comparison with acids and salts.
Similar calculations can be compared with Sodium Hydroxide (NaOH) and Potassium Hydroxide (KOH).
Where This Is Used
- Competitive exams and school chemistry tests.
- Lab work when preparing measured solutions.
- Real-world manufacturing and quality checks.
Common Mistakes When Calculating This
- Skipping subscripts in Ba(OH)₂ and miscounting atoms.
- Forgetting that parentheses in Ba(OH)₂ multiply the entire grouped part.
- Mixing up Ba element contribution with total molar mass.
- Reporting a value without units; final answer should be in g/mol for Barium Hydroxide.
Spot a slip early by comparing your work with molar mass before you hand in a final value.
Quick Revision
Formula: Ba(OH)2
Molar Mass: 171.34 g/mol
Key takeaway: count atoms accurately, multiply by atomic masses, and sum only at the end.
Formula Explanation
Ba(OH)2 contains Barium (Ba) (1), Oxygen (O) (2), Hydrogen (H) (2). Add each element contribution to get total molar mass.
FAQ
Conclusion
Molar Mass of Barium Hydroxide and Molar Mass of Ba(OH)₂ are now easy to revise with this structured page. You can use this method in exams, lab reports, and daily chemistry practice.