Molar Mass of Bromic Acid (HBrO3)
Molar Mass of Bromic Acid is a practical checkpoint before starting acid-base stoichiometry, especially in measured solution problems. Molar Mass of HBrO₃ is 128.91 g/mol, based on 3 element types, with Br contributing the largest share.
For fast checks, use the calculate molar mass, verify element values in the periodic table with molar mass, or explore more molar mass calculations.
Molar Mass of Bromic Acid is:
128.91 g/mol
Molar Mass of HBrO₃ equals 128.91 g/mol, so 128.91 grams is one mole.
Element Breakdown Table
| Element | Count | Atomic mass | Calculation | Contribution |
|---|---|---|---|---|
| Hydrogen (H) | 1 | 1.01 | 1 x 1.01 | 1.01 g/mol |
| Bromine (Br) | 1 | 79.90 | 1 x 79.90 | 79.90 g/mol |
| Oxygen (O) | 3 | 16.00 | 3 x 16.00 | 48.00 g/mol |
Final molar mass 1.010 + 79.900 + 48.000 | 128.91 g/mol | |||
Computing Molar Mass of Bromic Acid Step by Step
Molar Mass of Bromic Acid: Step-by-Step Calculation
1. Identify Element Counts
Read HBrO3 and list how many atoms of each element are present:
- 1 atom of Hydrogen (H)
- 1 atom of Bromine (Br)
- 3 atoms of Oxygen (O)
2. Determine Atomic Masses
Look up each element mass from the periodic table:
- Hydrogen (H) ~= 1.008 g/mol
- Bromine (Br) ~= 79.904 g/mol
- Oxygen (O) ~= 15.999 g/mol
3. Multiply Atomic Mass by Quantity
Multiply atom count by atomic mass for each element:
- Hydrogen (H): 1 x 1.008 = 1.010 g/mol
- Bromine (Br): 1 x 79.904 = 79.900 g/mol
- Oxygen (O): 3 x 15.999 = 48.000 g/mol
4. Sum Total Molar Mass
Add all contributions to get the final molar mass in g/mol.
Molar Mass = (1 x 1.008 + 1 x 79.904 + 3 x 15.999)
Molar Mass = 1.010 + 79.900 + 48.000
Molar Mass = 128.910 g/mol
Final rounded value shown on this page: 128.91 g/mol.
Visual Calculation Chart
| Element | Count | Mass | Count x mass | Contribution |
|---|---|---|---|---|
| Hydrogen (H) | 1 | 1.008 | 1 x 1.008 | = 1.010 |
| Bromine (Br) | 1 | 79.904 | 1 x 79.904 | = 79.900 |
| Oxygen (O) | 3 | 15.999 | 3 x 15.999 | = 48.000 |
Final molar mass 1.010 + 79.900 + 48.000 | = 128.910 | |||
Easy Way to Remember
Easy way to remember Molar Mass of Bromic Acid
- Molar Mass of Bromic Acid: count atoms, multiply masses, and add totals.
- Write each element in a table so you do not miss subscripts.
- Keep 2-3 decimals during steps, then round only at the end.
Use this checklist with molar mass whenever you want a quick confidence check.
Sample Reactions
| Type | Reaction |
|---|---|
| Neutralization | HCl + NaOH → NaCl + H₂O |
| Acid-carbonate | ₂HNO₃ + CaCO₃ → Ca(NO₃)₂ + H₂O + CO₂ |
Do You Know?
– Bromic Acid contains 3 element types: H, Br, O.
– Br contributes the largest share of this compound's total molar mass.
– In HBrO₃, O appears with the highest atom count.
– Its molar mass is 128.91 g/mol, which is used directly in gram-to-mole conversions.
– A common reaction for Bromic Acid is neutralization (HCl + NaOH → NaCl + H₂O).
Why This Compound Matters
Bromic Acid is important in acid-base work, especially when preparing safe measured solutions in lab sessions.
O chemistry is frequently tested in titration and neutralization chapters.
Similar calculations can be compared with Hydrobromic Acid (HBr) and Nitric Acid (HNO3).
Where This Is Used
- Competitive exams and school chemistry tests.
- Lab work when preparing measured solutions.
- Real-world manufacturing and quality checks.
Common Mistakes When Calculating This
- Skipping subscripts in HBrO₃ and miscounting atoms.
- Rounding atomic masses too early before finishing all multiplication steps.
- Mixing up Br element contribution with total molar mass.
- Reporting a value without units; final answer should be in g/mol for Bromic Acid.
Quick Revision
Formula: HBrO3
Molar Mass: 128.91 g/mol
Key takeaway: count atoms accurately, multiply by atomic masses, and sum only at the end.
Formula Explanation
HBrO3 contains Hydrogen (H) (1), Bromine (Br) (1), Oxygen (O) (3). Add each element contribution to get total molar mass.
FAQ
Conclusion
Molar Mass of Bromic Acid and Molar Mass of HBrO₃ are now easy to revise with this structured page. You can use this method in exams, lab reports, and daily chemistry practice.