Molar Mass of Butanol (C4H10O)
Molar Mass of Butanol is helpful for yield calculations and formula checks in carbon-chain reaction questions. Molar Mass of C₄H₁₀O is 74.12 g/mol, based on 3 element types, with C contributing the largest share.
For fast checks, use the molar mass calculator, verify element values in the periodic table, or explore more molar mass.
Molar Mass of Butanol is:
74.12 g/mol
Molar Mass of C₄H₁₀O equals 74.12 g/mol, so 74.12 grams is one mole.
Element Breakdown Table
| Element | Count | Atomic mass | Calculation | Contribution |
|---|---|---|---|---|
| Carbon (C) | 4 | 12.01 | 4 x 12.01 | 48.04 g/mol |
| Hydrogen (H) | 10 | 1.01 | 10 x 1.01 | 10.08 g/mol |
| Oxygen (O) | 1 | 16.00 | 1 x 16.00 | 16.00 g/mol |
Final molar mass 48.040 + 10.080 + 16.000 | 74.12 g/mol | |||
Computing Molar Mass of Butanol Step by Step
Molar Mass of Butanol: Step-by-Step Calculation
1. Identify Element Counts
Read C4H10O and list how many atoms of each element are present:
- 4 atoms of Carbon (C)
- 10 atoms of Hydrogen (H)
- 1 atom of Oxygen (O)
2. Determine Atomic Masses
Look up each element mass from the periodic table:
- Carbon (C) ~= 12.011 g/mol
- Hydrogen (H) ~= 1.008 g/mol
- Oxygen (O) ~= 15.999 g/mol
3. Multiply Atomic Mass by Quantity
Multiply atom count by atomic mass for each element:
- Carbon (C): 4 x 12.011 = 48.040 g/mol
- Hydrogen (H): 10 x 1.008 = 10.080 g/mol
- Oxygen (O): 1 x 15.999 = 16.000 g/mol
4. Sum Total Molar Mass
Add all contributions to get the final molar mass in g/mol.
Molar Mass = (4 x 12.011 + 10 x 1.008 + 1 x 15.999)
Molar Mass = 48.040 + 10.080 + 16.000
Molar Mass = 74.120 g/mol
Final rounded value shown on this page: 74.12 g/mol.
Visual Calculation Chart
| Element | Count | Mass | Count x mass | Contribution |
|---|---|---|---|---|
| Carbon (C) | 4 | 12.011 | 4 x 12.011 | = 48.040 |
| Hydrogen (H) | 10 | 1.008 | 10 x 1.008 | = 10.080 |
| Oxygen (O) | 1 | 15.999 | 1 x 15.999 | = 16.000 |
Final molar mass 48.040 + 10.080 + 16.000 | = 74.120 | |||
Easy Way to Remember
Easy way to remember Molar Mass of Butanol
- Molar Mass of Butanol: count atoms, multiply masses, and add totals.
- Write each element in a table so you do not miss subscripts.
- Keep 2-3 decimals during steps, then round only at the end.
Sample Reactions
| Type | Reaction |
|---|---|
| Combustion | C₄H₁₀O + ₆O₂ → ₄CO₂ + ₅H₂O |
| Sodium reaction | ₂C₄H₁₀O + ₂Na → ₂C₄H₉ONa + H₂ |
Do You Know?
– Butanol contains 3 element types: C, H, O.
– C contributes the largest share of this compound's total molar mass.
– In C₄H₁₀O, H appears with the highest atom count.
– Its molar mass is 74.12 g/mol, which is used directly in gram-to-mole conversions.
– A common reaction for Butanol is combustion (C₄H₁₀O + ₆O₂ → ₄CO₂ + ₅H₂O).
Why This Compound Matters
Butanol matters in organic chemistry, especially for fuel, solvent, or carbon-chain analysis.
Its formula pattern helps students practice molecular composition and yield calculation methods.
Similar calculations can be compared with Methanol (CH3OH) and Ethanol (C2H6O).
Where This Is Used
- Competitive exams and school chemistry tests.
- Lab work when preparing measured solutions.
- Real-world manufacturing and quality checks.
Common Mistakes When Calculating This
- Skipping subscripts in C₄H₁₀O and miscounting atoms.
- Rounding atomic masses too early before finishing all multiplication steps.
- Mixing up C element contribution with total molar mass.
- Reporting a value without units; final answer should be in g/mol for Butanol.
Quick Revision
Formula: C4H10O
Molar Mass: 74.12 g/mol
Key takeaway: count atoms accurately, multiply by atomic masses, and sum only at the end.
Formula Explanation
C4H10O contains Carbon (C) (4), Hydrogen (H) (10), Oxygen (O) (1). Add each element contribution to get total molar mass.
Keep molar mass page open while practicing so your totals match the same method shown here.
FAQ
Conclusion
Molar Mass of Butanol and Molar Mass of C₄H₁₀O are now easy to revise with this structured page. You can use this method in exams, lab reports, and daily chemistry practice.