Molar Mass of Chlorooctane (C8H17Cl)
Molar Mass of Chlorooctane is often referenced when connecting molecular structure to quantitative conversion steps. Molar Mass of C₈H₁₇Cl is 148.67 g/mol, based on 3 element types, with C contributing the largest share.
For fast checks, use the calculate molar mass, verify element values in the periodic table with molar mass, or explore more molar mass page.
Molar Mass of Chlorooctane is:
148.67 g/mol
Molar Mass of C₈H₁₇Cl equals 148.67 g/mol, so 148.67 grams is one mole.
Element Breakdown Table
| Element | Count | Atomic mass | Calculation | Contribution |
|---|---|---|---|---|
| Carbon (C) | 8 | 12.01 | 8 x 12.01 | 96.09 g/mol |
| Hydrogen (H) | 17 | 1.01 | 17 x 1.01 | 17.14 g/mol |
| Chlorine (Cl) | 1 | 35.45 | 1 x 35.45 | 35.45 g/mol |
Final molar mass 96.090 + 17.140 + 35.450 | 148.67 g/mol | |||
Computing Molar Mass of Chlorooctane Step by Step
Molar Mass of Chlorooctane: Step-by-Step Calculation
1. Identify Element Counts
Read C8H17Cl and list how many atoms of each element are present:
- 8 atoms of Carbon (C)
- 17 atoms of Hydrogen (H)
- 1 atom of Chlorine (Cl)
2. Determine Atomic Masses
Look up each element mass from the periodic table:
- Carbon (C) ~= 12.011 g/mol
- Hydrogen (H) ~= 1.008 g/mol
- Chlorine (Cl) ~= 35.450 g/mol
3. Multiply Atomic Mass by Quantity
Multiply atom count by atomic mass for each element:
- Carbon (C): 8 x 12.011 = 96.090 g/mol
- Hydrogen (H): 17 x 1.008 = 17.140 g/mol
- Chlorine (Cl): 1 x 35.450 = 35.450 g/mol
4. Sum Total Molar Mass
Add all contributions to get the final molar mass in g/mol.
Molar Mass = (8 x 12.011 + 17 x 1.008 + 1 x 35.450)
Molar Mass = 96.090 + 17.140 + 35.450
Molar Mass = 148.670 g/mol
Final rounded value shown on this page: 148.67 g/mol.
Visual Calculation Chart
| Element | Count | Mass | Count x mass | Contribution |
|---|---|---|---|---|
| Carbon (C) | 8 | 12.011 | 8 x 12.011 | = 96.090 |
| Hydrogen (H) | 17 | 1.008 | 17 x 1.008 | = 17.140 |
| Chlorine (Cl) | 1 | 35.450 | 1 x 35.450 | = 35.450 |
Final molar mass 96.090 + 17.140 + 35.450 | = 148.670 | |||
Easy Way to Remember
Easy way to remember Molar Mass of Chlorooctane
- Molar Mass of Chlorooctane: count atoms, multiply masses, and add totals.
- Write each element in a table so you do not miss subscripts.
- Keep 2-3 decimals during steps, then round only at the end.
Sample Reactions
| Type | Reaction |
|---|---|
| Synthesis | ₂H₂ + O₂ → ₂H₂O |
| Combustion | CH₄ + ₂O₂ → CO₂ + ₂H₂O |
Do You Know?
– Chlorooctane contains 3 element types: C, H, Cl.
– C contributes the largest share of this compound's total molar mass.
– In C₈H₁₇Cl, H appears with the highest atom count.
– Its molar mass is 148.67 g/mol, which is used directly in gram-to-mole conversions.
– A common reaction for Chlorooctane is synthesis (₂H₂ + O₂ → ₂H₂O).
Why This Compound Matters
Chlorooctane matters in organic chemistry, especially for fuel, solvent, or carbon-chain analysis.
Its formula pattern helps students practice molecular composition and yield calculation methods.
Similar calculations can be compared with Chloromethane (C1H3Cl) and Chloroethane (C2H5Cl).
Where This Is Used
- Competitive exams and school chemistry tests.
- Lab work when preparing measured solutions.
- Real-world manufacturing and quality checks.
Common Mistakes When Calculating This
- Skipping subscripts in C₈H₁₇Cl and miscounting atoms.
- Rounding atomic masses too early before finishing all multiplication steps.
- Mixing up C element contribution with total molar mass.
- Reporting a value without units; final answer should be in g/mol for Chlorooctane.
Spot a slip early by comparing your work with molar mass page before you hand in a final value.
Quick Revision
Formula: C8H17Cl
Molar Mass: 148.67 g/mol
Key takeaway: count atoms accurately, multiply by atomic masses, and sum only at the end.
Formula Explanation
C8H17Cl contains Carbon (C) (8), Hydrogen (H) (17), Chlorine (Cl) (1). Add each element contribution to get total molar mass.
FAQ
Conclusion
Molar Mass of Chlorooctane and Molar Mass of C₈H₁₇Cl are now easy to revise with this structured page. You can use this method in exams, lab reports, and daily chemistry practice.