Molar Mass of Chromium(III) Bromide (CrBr3)
Molar Mass of Chromium(III) Bromide is commonly used in ionic-equation practice and concentration calculations for salt solutions. Molar Mass of CrBr₃ is 291.71 g/mol, based on 2 element types, with Br contributing the largest share.
For fast checks, use the calculate molar mass, verify element values in the periodic table with molar mass, or explore more molar mass calculations.
Molar Mass of Chromium(III) Bromide is:
291.71 g/mol
Molar Mass of CrBr₃ equals 291.71 g/mol, so 291.71 grams is one mole.
Element Breakdown Table
| Element | Count | Atomic mass | Calculation | Contribution |
|---|---|---|---|---|
| Chromium (Cr) | 1 | 52.00 | 1 x 52.00 | 52.00 g/mol |
| Bromine (Br) | 3 | 79.90 | 3 x 79.90 | 239.71 g/mol |
Final molar mass 52.000 + 239.710 | 291.71 g/mol | |||
Computing Molar Mass of Chromium(III) Bromide Step by Step
Molar Mass of Chromium(III) Bromide: Step-by-Step Calculation
1. Identify Element Counts
Read CrBr3 and list how many atoms of each element are present:
- 1 atom of Chromium (Cr)
- 3 atoms of Bromine (Br)
2. Determine Atomic Masses
Look up each element mass from the periodic table:
- Chromium (Cr) ~= 51.996 g/mol
- Bromine (Br) ~= 79.904 g/mol
3. Multiply Atomic Mass by Quantity
Multiply atom count by atomic mass for each element:
- Chromium (Cr): 1 x 51.996 = 52.000 g/mol
- Bromine (Br): 3 x 79.904 = 239.710 g/mol
4. Sum Total Molar Mass
Add all contributions to get the final molar mass in g/mol.
Molar Mass = (1 x 51.996 + 3 x 79.904)
Molar Mass = 52.000 + 239.710
Molar Mass = 291.710 g/mol
Final rounded value shown on this page: 291.71 g/mol.
Visual Calculation Chart
| Element | Count | Mass | Count x mass | Contribution |
|---|---|---|---|---|
| Chromium (Cr) | 1 | 51.996 | 1 x 51.996 | = 52.000 |
| Bromine (Br) | 3 | 79.904 | 3 x 79.904 | = 239.710 |
Final molar mass 52.000 + 239.710 | = 291.710 | |||
Easy Way to Remember
Easy way to remember Molar Mass of Chromium(III) Bromide
- Molar Mass of Chromium(III) Bromide: count atoms, multiply masses, and add totals.
- Write each element in a table so you do not miss subscripts.
- Keep 2-3 decimals during steps, then round only at the end.
Sample Reactions
| Type | Reaction |
|---|---|
| Double displacement | AgNO₃ + NaCl → AgCl + NaNO₃ |
| Acid-salt reaction | Na₂CO₃ + ₂HCl → ₂NaCl + H₂O + CO₂ |
Do You Know?
– Chromium(III) Bromide contains 2 element types: Cr, Br.
– Br contributes the largest share of this compound's total molar mass.
– In CrBr₃, Br appears with the highest atom count.
– Its molar mass is 291.71 g/mol, which is used directly in gram-to-mole conversions.
– A common reaction for Chromium(III) Bromide is double displacement (AgNO₃ + NaCl → AgCl + NaNO₃).
Why This Compound Matters
Chromium(III) Bromide appears in ionic-reaction practice and precipitation examples in school chemistry.
Its molar mass helps students move quickly between grams, moles, and concentration problems.
Similar calculations can be compared with Sodium Bromide (NaBr) and Sodium Chromate (Na2CrO4).
Where This Is Used
- Competitive exams and school chemistry tests.
- Lab work when preparing measured solutions.
- Real-world manufacturing and quality checks.
Common Mistakes When Calculating This
- Skipping subscripts in CrBr₃ and miscounting atoms.
- Rounding atomic masses too early before finishing all multiplication steps.
- Mixing up Br element contribution with total molar mass.
- Reporting a value without units; final answer should be in g/mol for Chromium(III) Bromide.
Spot a slip early by comparing your work with molar mass page before you hand in a final value.
Quick Revision
Formula: CrBr3
Molar Mass: 291.71 g/mol
Key takeaway: count atoms accurately, multiply by atomic masses, and sum only at the end.
Formula Explanation
CrBr3 contains Chromium (Cr) (1), Bromine (Br) (3). Add each element contribution to get total molar mass.
FAQ
Conclusion
Molar Mass of Chromium(III) Bromide and Molar Mass of CrBr₃ are now easy to revise with this structured page. You can use this method in exams, lab reports, and daily chemistry practice.