Molar Mass of Iron(II) Iodide (FeI2)
Molar Mass of Iron(II) Iodide is a key number in salt-related stoichiometry, especially when balancing reactants and products. Molar Mass of FeI₂ is 309.65 g/mol, based on 2 element types, with I contributing the largest share.
For fast checks, use the molar mass calculator, verify element values in the periodic table, or explore more molar mass page.
Molar Mass of Iron(II) Iodide is:
309.65 g/mol
Molar Mass of FeI₂ equals 309.65 g/mol, so 309.65 grams is one mole.
Element Breakdown Table
| Element | Count | Atomic mass | Calculation | Contribution |
|---|---|---|---|---|
| Iron (Fe) | 1 | 55.84 | 1 x 55.84 | 55.84 g/mol |
| Iodine (I) | 2 | 126.90 | 2 x 126.90 | 253.81 g/mol |
Final molar mass 55.840 + 253.810 | 309.65 g/mol | |||
Computing Molar Mass of Iron(II) Iodide Step by Step
Molar Mass of Iron(II) Iodide: Step-by-Step Calculation
1. Identify Element Counts
Read FeI2 and list how many atoms of each element are present:
- 1 atom of Iron (Fe)
- 2 atoms of Iodine (I)
2. Determine Atomic Masses
Look up each element mass from the periodic table:
- Iron (Fe) ~= 55.845 g/mol
- Iodine (I) ~= 126.904 g/mol
3. Multiply Atomic Mass by Quantity
Multiply atom count by atomic mass for each element:
- Iron (Fe): 1 x 55.845 = 55.840 g/mol
- Iodine (I): 2 x 126.904 = 253.810 g/mol
4. Sum Total Molar Mass
Add all contributions to get the final molar mass in g/mol.
Molar Mass = (1 x 55.845 + 2 x 126.904)
Molar Mass = 55.840 + 253.810
Molar Mass = 309.650 g/mol
Final rounded value shown on this page: 309.65 g/mol.
Visual Calculation Chart
| Element | Count | Mass | Count x mass | Contribution |
|---|---|---|---|---|
| Iron (Fe) | 1 | 55.845 | 1 x 55.845 | = 55.840 |
| Iodine (I) | 2 | 126.904 | 2 x 126.904 | = 253.810 |
Final molar mass 55.840 + 253.810 | = 309.650 | |||
Easy Way to Remember
Easy way to remember Molar Mass of Iron(II) Iodide
- Molar Mass of Iron(II) Iodide: count atoms, multiply masses, and add totals.
- Write each element in a table so you do not miss subscripts.
- Keep 2-3 decimals during steps, then round only at the end.
Sample Reactions
| Type | Reaction |
|---|---|
| Double displacement | AgNO₃ + NaCl → AgCl + NaNO₃ |
| Acid-salt reaction | Na₂CO₃ + ₂HCl → ₂NaCl + H₂O + CO₂ |
Do You Know?
– Iron(II) Iodide contains 2 element types: Fe, I.
– I contributes the largest share of this compound's total molar mass.
– In FeI₂, I appears with the highest atom count.
– Its molar mass is 309.65 g/mol, which is used directly in gram-to-mole conversions.
– A common reaction for Iron(II) Iodide is double displacement (AgNO₃ + NaCl → AgCl + NaNO₃).
Why This Compound Matters
Iron(II) Iodide appears in ionic-reaction practice and precipitation examples in school chemistry.
Its molar mass helps students move quickly between grams, moles, and concentration problems.
Similar calculations can be compared with Iron(III) Iodide (FeI3) and Sodium Iodide (NaI).
Where This Is Used
- Competitive exams and school chemistry tests.
- Lab work when preparing measured solutions.
- Real-world manufacturing and quality checks.
Common Mistakes When Calculating This
- Skipping subscripts in FeI₂ and miscounting atoms.
- Rounding atomic masses too early before finishing all multiplication steps.
- Mixing up I element contribution with total molar mass.
- Reporting a value without units; final answer should be in g/mol for Iron(II) Iodide.
Quick Revision
Formula: FeI2
Molar Mass: 309.65 g/mol
Key takeaway: count atoms accurately, multiply by atomic masses, and sum only at the end.
Before a test, molar mass helps you review more formulas without rebuilding each table manually.
Formula Explanation
FeI2 contains Iron (Fe) (1), Iodine (I) (2). Add each element contribution to get total molar mass.
FAQ
Conclusion
Molar Mass of Iron(II) Iodide and Molar Mass of FeI₂ are now easy to revise with this structured page. You can use this method in exams, lab reports, and daily chemistry practice.