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Molar Mass Lab/Molar mass for C9H20O
Organic

Molar Mass of Nonanol (C9H20O)

Molar Mass of Nonanol is helpful for yield calculations and formula checks in carbon-chain reaction questions. Molar Mass of C₉H₂₀O is 144.26 g/mol, based on 3 element types, with C contributing the largest share.

For fast checks, use the molar mass calculator, verify element values in the periodic table, or explore more molar mass.

Molar Mass of Nonanol is:

144.26 g/mol

Molar Mass of C₉H₂₀O equals 144.26 g/mol, so 144.26 grams is one mole.

Element Breakdown Table

ElementCountAtomic massCalculationContribution
Carbon (C)912.019 x 12.01108.10 g/mol
Hydrogen (H)201.0120 x 1.0120.16 g/mol
Oxygen (O)116.001 x 16.0016.00 g/mol
Final molar mass
108.100 + 20.160 + 16.000
144.26 g/mol

Computing Molar Mass of Nonanol Step by Step

Molar Mass of Nonanol: Step-by-Step Calculation

1. Identify Element Counts

Read C9H20O and list how many atoms of each element are present:

  1. 9 atoms of Carbon (C)
  2. 20 atoms of Hydrogen (H)
  3. 1 atom of Oxygen (O)

2. Determine Atomic Masses

Look up each element mass from the periodic table:

  1. Carbon (C) ~= 12.011 g/mol
  2. Hydrogen (H) ~= 1.008 g/mol
  3. Oxygen (O) ~= 15.999 g/mol

3. Multiply Atomic Mass by Quantity

Multiply atom count by atomic mass for each element:

  • Carbon (C): 9 x 12.011 = 108.100 g/mol
  • Hydrogen (H): 20 x 1.008 = 20.160 g/mol
  • Oxygen (O): 1 x 15.999 = 16.000 g/mol

4. Sum Total Molar Mass

Add all contributions to get the final molar mass in g/mol.

Molar Mass = (9 x 12.011 + 20 x 1.008 + 1 x 15.999)

Molar Mass = 108.100 + 20.160 + 16.000

Molar Mass = 144.260 g/mol

Final rounded value shown on this page: 144.26 g/mol.

Visual Calculation Chart

ElementCountMassCount x massContribution
Carbon (C)912.0119 x 12.011= 108.100
Hydrogen (H)201.00820 x 1.008= 20.160
Oxygen (O)115.9991 x 15.999= 16.000
Final molar mass
108.100 + 20.160 + 16.000
= 144.260

Easy Way to Remember

Easy way to remember Molar Mass of Nonanol

  • Molar Mass of Nonanol: count atoms, multiply masses, and add totals.
  • Write each element in a table so you do not miss subscripts.
  • Keep 2-3 decimals during steps, then round only at the end.

Sample Reactions

TypeReaction
CombustionC₉H₂₀O + ₁₃.₅O₂ → ₉CO₂ + ₁₀H₂O
Sodium reaction₂C₉H₂₀O + ₂Na → ₂C₉H₁₉ONa + H₂

Do You Know?

Nonanol contains 3 element types: C, H, O.

C contributes the largest share of this compound's total molar mass.

In C₉H₂₀O, H appears with the highest atom count.

Its molar mass is 144.26 g/mol, which is used directly in gram-to-mole conversions.

A common reaction for Nonanol is combustion (C₉H₂₀O + ₁₃.₅O₂ → ₉CO₂ + ₁₀H₂O).

Why This Compound Matters

Nonanol matters in organic chemistry, especially for fuel, solvent, or carbon-chain analysis.

Its formula pattern helps students practice molecular composition and yield calculation methods.

Similar calculations can be compared with Methanol (CH3OH) and Ethanol (C2H6O).

Where This Is Used

  • Competitive exams and school chemistry tests.
  • Lab work when preparing measured solutions.
  • Real-world manufacturing and quality checks.

Common Mistakes When Calculating This

  • Skipping subscripts in C₉H₂₀O and miscounting atoms.
  • Rounding atomic masses too early before finishing all multiplication steps.
  • Mixing up C element contribution with total molar mass.
  • Reporting a value without units; final answer should be in g/mol for Nonanol.

Quick Revision

Formula: C9H20O

Molar Mass: 144.26 g/mol

Key takeaway: count atoms accurately, multiply by atomic masses, and sum only at the end.

Formula Explanation

C9H20O contains Carbon (C) (9), Hydrogen (H) (20), Oxygen (O) (1). Add each element contribution to get total molar mass.

Molar Mass = Sum (atomic mass of each element x atom count)

Keep molar mass guide open while practicing so your totals match the same method shown here.

FAQ

The molar mass of C9H20O is 144.26 g/mol based on atomic masses and atom counts.

Conclusion

Molar Mass of Nonanol and Molar Mass of C₉H₂₀O are now easy to revise with this structured page. You can use this method in exams, lab reports, and daily chemistry practice.