Molar Mass of Tetradecanol (C14H30O)
Molar Mass of Tetradecanol is often referenced when connecting molecular structure to quantitative conversion steps. Molar Mass of C₁₄H₃₀O is 214.39 g/mol, based on 3 element types, with C contributing the largest share.
For fast checks, use the calculate molar mass, verify element values in the periodic table with molar mass, or explore more molar mass page.
Molar Mass of Tetradecanol is:
214.39 g/mol
Molar Mass of C₁₄H₃₀O equals 214.39 g/mol, so 214.39 grams is one mole.
Element Breakdown Table
| Element | Count | Atomic mass | Calculation | Contribution |
|---|---|---|---|---|
| Carbon (C) | 14 | 12.01 | 14 x 12.01 | 168.15 g/mol |
| Hydrogen (H) | 30 | 1.01 | 30 x 1.01 | 30.24 g/mol |
| Oxygen (O) | 1 | 16.00 | 1 x 16.00 | 16.00 g/mol |
Final molar mass 168.150 + 30.240 + 16.000 | 214.39 g/mol | |||
Computing Molar Mass of Tetradecanol Step by Step
Molar Mass of Tetradecanol: Step-by-Step Calculation
1. Identify Element Counts
Read C14H30O and list how many atoms of each element are present:
- 14 atoms of Carbon (C)
- 30 atoms of Hydrogen (H)
- 1 atom of Oxygen (O)
2. Determine Atomic Masses
Look up each element mass from the periodic table:
- Carbon (C) ~= 12.011 g/mol
- Hydrogen (H) ~= 1.008 g/mol
- Oxygen (O) ~= 15.999 g/mol
3. Multiply Atomic Mass by Quantity
Multiply atom count by atomic mass for each element:
- Carbon (C): 14 x 12.011 = 168.150 g/mol
- Hydrogen (H): 30 x 1.008 = 30.240 g/mol
- Oxygen (O): 1 x 15.999 = 16.000 g/mol
4. Sum Total Molar Mass
Add all contributions to get the final molar mass in g/mol.
Molar Mass = (14 x 12.011 + 30 x 1.008 + 1 x 15.999)
Molar Mass = 168.150 + 30.240 + 16.000
Molar Mass = 214.390 g/mol
Final rounded value shown on this page: 214.39 g/mol.
Visual Calculation Chart
| Element | Count | Mass | Count x mass | Contribution |
|---|---|---|---|---|
| Carbon (C) | 14 | 12.011 | 14 x 12.011 | = 168.150 |
| Hydrogen (H) | 30 | 1.008 | 30 x 1.008 | = 30.240 |
| Oxygen (O) | 1 | 15.999 | 1 x 15.999 | = 16.000 |
Final molar mass 168.150 + 30.240 + 16.000 | = 214.390 | |||
Easy Way to Remember
Easy way to remember Molar Mass of Tetradecanol
- Molar Mass of Tetradecanol: count atoms, multiply masses, and add totals.
- Write each element in a table so you do not miss subscripts.
- Keep 2-3 decimals during steps, then round only at the end.
Sample Reactions
| Type | Reaction |
|---|---|
| Combustion | C₁₄H₃₀O + ₂₁O₂ → ₁₄CO₂ + ₁₅H₂O |
| Sodium reaction | ₂C₁₄H₃₀O + ₂Na → ₂C₁₄H₂₉ONa + H₂ |
Do You Know?
– Tetradecanol contains 3 element types: C, H, O.
– C contributes the largest share of this compound's total molar mass.
– In C₁₄H₃₀O, H appears with the highest atom count.
– Its molar mass is 214.39 g/mol, which is used directly in gram-to-mole conversions.
– A common reaction for Tetradecanol is combustion (C₁₄H₃₀O + ₂₁O₂ → ₁₄CO₂ + ₁₅H₂O).
For more examples in the same format, browse the related formulas on molar mass page.
Why This Compound Matters
Tetradecanol matters in organic chemistry, especially for fuel, solvent, or carbon-chain analysis.
Its formula pattern helps students practice molecular composition and yield calculation methods.
Similar calculations can be compared with Methanol (CH3OH) and Ethanol (C2H6O).
Where This Is Used
- Competitive exams and school chemistry tests.
- Lab work when preparing measured solutions.
- Real-world manufacturing and quality checks.
Common Mistakes When Calculating This
- Skipping subscripts in C₁₄H₃₀O and miscounting atoms.
- Rounding atomic masses too early before finishing all multiplication steps.
- Mixing up C element contribution with total molar mass.
- Reporting a value without units; final answer should be in g/mol for Tetradecanol.
Quick Revision
Formula: C14H30O
Molar Mass: 214.39 g/mol
Key takeaway: count atoms accurately, multiply by atomic masses, and sum only at the end.
Formula Explanation
C14H30O contains Carbon (C) (14), Hydrogen (H) (30), Oxygen (O) (1). Add each element contribution to get total molar mass.
FAQ
Conclusion
Molar Mass of Tetradecanol and Molar Mass of C₁₄H₃₀O are now easy to revise with this structured page. You can use this method in exams, lab reports, and daily chemistry practice.