Molar Mass of Tridecanol (C13H28O)
Molar Mass of Tridecanol is often referenced when connecting molecular structure to quantitative conversion steps. Molar Mass of C₁₃H₂₈O is 200.37 g/mol, based on 3 element types, with C contributing the largest share.
For fast checks, use the calculate molar mass, verify element values in the periodic table with molar mass, or explore more molar mass page.
Molar Mass of Tridecanol is:
200.37 g/mol
Molar Mass of C₁₃H₂₈O equals 200.37 g/mol, so 200.37 grams is one mole.
Element Breakdown Table
| Element | Count | Atomic mass | Calculation | Contribution |
|---|---|---|---|---|
| Carbon (C) | 13 | 12.01 | 13 x 12.01 | 156.14 g/mol |
| Hydrogen (H) | 28 | 1.01 | 28 x 1.01 | 28.22 g/mol |
| Oxygen (O) | 1 | 16.00 | 1 x 16.00 | 16.00 g/mol |
Final molar mass 156.140 + 28.220 + 16.000 | 200.37 g/mol | |||
Computing Molar Mass of Tridecanol Step by Step
Molar Mass of Tridecanol: Step-by-Step Calculation
1. Identify Element Counts
Read C13H28O and list how many atoms of each element are present:
- 13 atoms of Carbon (C)
- 28 atoms of Hydrogen (H)
- 1 atom of Oxygen (O)
2. Determine Atomic Masses
Look up each element mass from the periodic table:
- Carbon (C) ~= 12.011 g/mol
- Hydrogen (H) ~= 1.008 g/mol
- Oxygen (O) ~= 15.999 g/mol
3. Multiply Atomic Mass by Quantity
Multiply atom count by atomic mass for each element:
- Carbon (C): 13 x 12.011 = 156.140 g/mol
- Hydrogen (H): 28 x 1.008 = 28.220 g/mol
- Oxygen (O): 1 x 15.999 = 16.000 g/mol
4. Sum Total Molar Mass
Add all contributions to get the final molar mass in g/mol.
Molar Mass = (13 x 12.011 + 28 x 1.008 + 1 x 15.999)
Molar Mass = 156.140 + 28.220 + 16.000
Molar Mass = 200.370 g/mol
Final rounded value shown on this page: 200.37 g/mol.
Visual Calculation Chart
| Element | Count | Mass | Count x mass | Contribution |
|---|---|---|---|---|
| Carbon (C) | 13 | 12.011 | 13 x 12.011 | = 156.140 |
| Hydrogen (H) | 28 | 1.008 | 28 x 1.008 | = 28.220 |
| Oxygen (O) | 1 | 15.999 | 1 x 15.999 | = 16.000 |
Final molar mass 156.140 + 28.220 + 16.000 | = 200.370 | |||
Easy Way to Remember
Easy way to remember Molar Mass of Tridecanol
- Molar Mass of Tridecanol: count atoms, multiply masses, and add totals.
- Write each element in a table so you do not miss subscripts.
- Keep 2-3 decimals during steps, then round only at the end.
Sample Reactions
| Type | Reaction |
|---|---|
| Combustion | C₁₃H₂₈O + ₁₉.₅O₂ → ₁₃CO₂ + ₁₄H₂O |
| Sodium reaction | ₂C₁₃H₂₈O + ₂Na → ₂C₁₃H₂₇ONa + H₂ |
Do You Know?
– Tridecanol contains 3 element types: C, H, O.
– C contributes the largest share of this compound's total molar mass.
– In C₁₃H₂₈O, H appears with the highest atom count.
– Its molar mass is 200.37 g/mol, which is used directly in gram-to-mole conversions.
– A common reaction for Tridecanol is combustion (C₁₃H₂₈O + ₁₉.₅O₂ → ₁₃CO₂ + ₁₄H₂O).
Why This Compound Matters
Tridecanol matters in organic chemistry, especially for fuel, solvent, or carbon-chain analysis.
Its formula pattern helps students practice molecular composition and yield calculation methods.
Similar calculations can be compared with Methanol (CH3OH) and Ethanol (C2H6O).
For broader practice beyond this compound, molar mass calculations keeps classroom examples one click away.
Where This Is Used
- Competitive exams and school chemistry tests.
- Lab work when preparing measured solutions.
- Real-world manufacturing and quality checks.
Common Mistakes When Calculating This
- Skipping subscripts in C₁₃H₂₈O and miscounting atoms.
- Rounding atomic masses too early before finishing all multiplication steps.
- Mixing up C element contribution with total molar mass.
- Reporting a value without units; final answer should be in g/mol for Tridecanol.
Quick Revision
Formula: C13H28O
Molar Mass: 200.37 g/mol
Key takeaway: count atoms accurately, multiply by atomic masses, and sum only at the end.
Formula Explanation
C13H28O contains Carbon (C) (13), Hydrogen (H) (28), Oxygen (O) (1). Add each element contribution to get total molar mass.
FAQ
Conclusion
Molar Mass of Tridecanol and Molar Mass of C₁₃H₂₈O are now easy to revise with this structured page. You can use this method in exams, lab reports, and daily chemistry practice.