Molar Mass of Undecanol (C11H24O)
Molar Mass of Undecanol is often referenced when connecting molecular structure to quantitative conversion steps. Molar Mass of C₁₁H₂₄O is 172.31 g/mol, based on 3 element types, with C contributing the largest share.
For fast checks, use the calculate molar mass, verify element values in the periodic table with molar mass, or explore more molar mass page.
Molar Mass of Undecanol is:
172.31 g/mol
Molar Mass of C₁₁H₂₄O equals 172.31 g/mol, so 172.31 grams is one mole.
Element Breakdown Table
| Element | Count | Atomic mass | Calculation | Contribution |
|---|---|---|---|---|
| Carbon (C) | 11 | 12.01 | 11 x 12.01 | 132.12 g/mol |
| Hydrogen (H) | 24 | 1.01 | 24 x 1.01 | 24.19 g/mol |
| Oxygen (O) | 1 | 16.00 | 1 x 16.00 | 16.00 g/mol |
Final molar mass 132.120 + 24.190 + 16.000 | 172.31 g/mol | |||
Computing Molar Mass of Undecanol Step by Step
Molar Mass of Undecanol: Step-by-Step Calculation
1. Identify Element Counts
Read C11H24O and list how many atoms of each element are present:
- 11 atoms of Carbon (C)
- 24 atoms of Hydrogen (H)
- 1 atom of Oxygen (O)
2. Determine Atomic Masses
Look up each element mass from the periodic table:
- Carbon (C) ~= 12.011 g/mol
- Hydrogen (H) ~= 1.008 g/mol
- Oxygen (O) ~= 15.999 g/mol
3. Multiply Atomic Mass by Quantity
Multiply atom count by atomic mass for each element:
- Carbon (C): 11 x 12.011 = 132.120 g/mol
- Hydrogen (H): 24 x 1.008 = 24.190 g/mol
- Oxygen (O): 1 x 15.999 = 16.000 g/mol
4. Sum Total Molar Mass
Add all contributions to get the final molar mass in g/mol.
Molar Mass = (11 x 12.011 + 24 x 1.008 + 1 x 15.999)
Molar Mass = 132.120 + 24.190 + 16.000
Molar Mass = 172.310 g/mol
Final rounded value shown on this page: 172.31 g/mol.
Visual Calculation Chart
| Element | Count | Mass | Count x mass | Contribution |
|---|---|---|---|---|
| Carbon (C) | 11 | 12.011 | 11 x 12.011 | = 132.120 |
| Hydrogen (H) | 24 | 1.008 | 24 x 1.008 | = 24.190 |
| Oxygen (O) | 1 | 15.999 | 1 x 15.999 | = 16.000 |
Final molar mass 132.120 + 24.190 + 16.000 | = 172.310 | |||
Easy Way to Remember
Easy way to remember Molar Mass of Undecanol
- Molar Mass of Undecanol: count atoms, multiply masses, and add totals.
- Write each element in a table so you do not miss subscripts.
- Keep 2-3 decimals during steps, then round only at the end.
Sample Reactions
| Type | Reaction |
|---|---|
| Combustion | C₁₁H₂₄O + ₁₆.₅O₂ → ₁₁CO₂ + ₁₂H₂O |
| Sodium reaction | ₂C₁₁H₂₄O + ₂Na → ₂C₁₁H₂₃ONa + H₂ |
Use these reactions with molar mass guide when you need the molar mass for each species.
Do You Know?
– Undecanol contains 3 element types: C, H, O.
– C contributes the largest share of this compound's total molar mass.
– In C₁₁H₂₄O, H appears with the highest atom count.
– Its molar mass is 172.31 g/mol, which is used directly in gram-to-mole conversions.
– A common reaction for Undecanol is combustion (C₁₁H₂₄O + ₁₆.₅O₂ → ₁₁CO₂ + ₁₂H₂O).
Why This Compound Matters
Undecanol matters in organic chemistry, especially for fuel, solvent, or carbon-chain analysis.
Its formula pattern helps students practice molecular composition and yield calculation methods.
Similar calculations can be compared with Methanol (CH3OH) and Ethanol (C2H6O).
Where This Is Used
- Competitive exams and school chemistry tests.
- Lab work when preparing measured solutions.
- Real-world manufacturing and quality checks.
Common Mistakes When Calculating This
- Skipping subscripts in C₁₁H₂₄O and miscounting atoms.
- Rounding atomic masses too early before finishing all multiplication steps.
- Mixing up C element contribution with total molar mass.
- Reporting a value without units; final answer should be in g/mol for Undecanol.
Quick Revision
Formula: C11H24O
Molar Mass: 172.31 g/mol
Key takeaway: count atoms accurately, multiply by atomic masses, and sum only at the end.
Formula Explanation
C11H24O contains Carbon (C) (11), Hydrogen (H) (24), Oxygen (O) (1). Add each element contribution to get total molar mass.
FAQ
Conclusion
Molar Mass of Undecanol and Molar Mass of C₁₁H₂₄O are now easy to revise with this structured page. You can use this method in exams, lab reports, and daily chemistry practice.