Molar Mass of Bromodecane (C10H21Br)
Molar Mass of Bromodecane supports organic chemistry work where composition and mass relationships are compared across carbon compounds. Molar Mass of C₁₀H₂₁Br is 221.18 g/mol, based on 3 element types, with C contributing the largest share.
For fast checks, use the molar mass calculator, verify element values in the periodic table, or explore more molar mass calculations.
Molar Mass of Bromodecane is:
221.18 g/mol
Molar Mass of C₁₀H₂₁Br equals 221.18 g/mol, so 221.18 grams is one mole.
Element Breakdown Table
| Element | Count | Atomic mass | Calculation | Contribution |
|---|---|---|---|---|
| Carbon (C) | 10 | 12.01 | 10 x 12.01 | 120.11 g/mol |
| Hydrogen (H) | 21 | 1.01 | 21 x 1.01 | 21.17 g/mol |
| Bromine (Br) | 1 | 79.90 | 1 x 79.90 | 79.90 g/mol |
Final molar mass 120.110 + 21.170 + 79.900 | 221.18 g/mol | |||
Computing Molar Mass of Bromodecane Step by Step
Molar Mass of Bromodecane: Step-by-Step Calculation
1. Identify Element Counts
Read C10H21Br and list how many atoms of each element are present:
- 10 atoms of Carbon (C)
- 21 atoms of Hydrogen (H)
- 1 atom of Bromine (Br)
2. Determine Atomic Masses
Look up each element mass from the periodic table:
- Carbon (C) ~= 12.011 g/mol
- Hydrogen (H) ~= 1.008 g/mol
- Bromine (Br) ~= 79.904 g/mol
3. Multiply Atomic Mass by Quantity
Multiply atom count by atomic mass for each element:
- Carbon (C): 10 x 12.011 = 120.110 g/mol
- Hydrogen (H): 21 x 1.008 = 21.170 g/mol
- Bromine (Br): 1 x 79.904 = 79.900 g/mol
4. Sum Total Molar Mass
Add all contributions to get the final molar mass in g/mol.
Molar Mass = (10 x 12.011 + 21 x 1.008 + 1 x 79.904)
Molar Mass = 120.110 + 21.170 + 79.900
Molar Mass = 221.180 g/mol
Final rounded value shown on this page: 221.18 g/mol.
Visual Calculation Chart
| Element | Count | Mass | Count x mass | Contribution |
|---|---|---|---|---|
| Carbon (C) | 10 | 12.011 | 10 x 12.011 | = 120.110 |
| Hydrogen (H) | 21 | 1.008 | 21 x 1.008 | = 21.170 |
| Bromine (Br) | 1 | 79.904 | 1 x 79.904 | = 79.900 |
Final molar mass 120.110 + 21.170 + 79.900 | = 221.180 | |||
Easy Way to Remember
Easy way to remember Molar Mass of Bromodecane
- Molar Mass of Bromodecane: count atoms, multiply masses, and add totals.
- Write each element in a table so you do not miss subscripts.
- Keep 2-3 decimals during steps, then round only at the end.
Sample Reactions
| Type | Reaction |
|---|---|
| Synthesis | ₂H₂ + O₂ → ₂H₂O |
| Combustion | CH₄ + ₂O₂ → CO₂ + ₂H₂O |
Do You Know?
– Bromodecane contains 3 element types: C, H, Br.
– C contributes the largest share of this compound's total molar mass.
– In C₁₀H₂₁Br, H appears with the highest atom count.
– Its molar mass is 221.18 g/mol, which is used directly in gram-to-mole conversions.
– A common reaction for Bromodecane is synthesis (₂H₂ + O₂ → ₂H₂O).
Why This Compound Matters
Bromodecane matters in organic chemistry, especially for fuel, solvent, or carbon-chain analysis.
Its formula pattern helps students practice molecular composition and yield calculation methods.
Similar calculations can be compared with Bromomethane (C1H3Br) and Bromoethane (C2H5Br).
For broader practice beyond this compound, molar mass calculations keeps classroom examples one click away.
Where This Is Used
- Competitive exams and school chemistry tests.
- Lab work when preparing measured solutions.
- Real-world manufacturing and quality checks.
Common Mistakes When Calculating This
- Skipping subscripts in C₁₀H₂₁Br and miscounting atoms.
- Rounding atomic masses too early before finishing all multiplication steps.
- Mixing up C element contribution with total molar mass.
- Reporting a value without units; final answer should be in g/mol for Bromodecane.
Quick Revision
Formula: C10H21Br
Molar Mass: 221.18 g/mol
Key takeaway: count atoms accurately, multiply by atomic masses, and sum only at the end.
Formula Explanation
C10H21Br contains Carbon (C) (10), Hydrogen (H) (21), Bromine (Br) (1). Add each element contribution to get total molar mass.
FAQ
Conclusion
Molar Mass of Bromodecane and Molar Mass of C₁₀H₂₁Br are now easy to revise with this structured page. You can use this method in exams, lab reports, and daily chemistry practice.