Organic

Molar Mass of Bromopropane (C₃H₇Br)

Molar Mass of Bromopropane is helpful for yield calculations and formula checks in carbon-chain reaction questions. Molar Mass of C₃H₇Br is 122.99 g/mol, based on 3 element types, with Br contributing the largest share.

For fast checks, use the molar mass calculator, verify element values in the periodic table, or explore more molar mass.

Molar Mass of Bromopropane is:

122.99 g/mol

Molar Mass of C₃H₇Br equals 122.99 g/mol, so 122.99 grams is one mole.

Element Breakdown Table

Element	Count	Atomic mass	Calculation	Contribution
Carbon (C)	3	12.01	3 x 12.01	36.03 g/mol
Hydrogen (H)	7	1.01	7 x 1.01	7.06 g/mol
Bromine (Br)	1	79.90	1 x 79.90	79.90 g/mol
Final molar mass 36.030 + 7.060 + 79.900				122.99 g/mol

Computing Molar Mass of Bromopropane Step by Step

Molar Mass of Bromopropane: Step-by-Step Calculation

1. Identify Element Counts

Read C₃H₇Br and list how many atoms of each element are present:

3 atoms of Carbon (C)
7 atoms of Hydrogen (H)
1 atom of Bromine (Br)

2. Determine Atomic Masses

Look up each element mass from the periodic table:

Carbon (C) ~= 12.011 g/mol
Hydrogen (H) ~= 1.008 g/mol
Bromine (Br) ~= 79.904 g/mol

3. Multiply Atomic Mass by Quantity

Multiply atom count by atomic mass for each element:

Carbon (C): 3 x 12.011 = 36.030 g/mol
Hydrogen (H): 7 x 1.008 = 7.060 g/mol
Bromine (Br): 1 x 79.904 = 79.900 g/mol

4. Sum Total Molar Mass

Add all contributions to get the final molar mass in g/mol.

Molar Mass = (3 x 12.011 + 7 x 1.008 + 1 x 79.904)

Molar Mass = 36.030 + 7.060 + 79.900

Molar Mass = 122.990 g/mol

Final rounded value shown on this page: 122.99 g/mol.

Visual Calculation Chart

Element	Count	Mass	Count x mass	Contribution
Carbon (C)	3	12.011	3 x 12.011	= 36.030
Hydrogen (H)	7	1.008	7 x 1.008	= 7.060
Bromine (Br)	1	79.904	1 x 79.904	= 79.900
Final molar mass 36.030 + 7.060 + 79.900				= 122.990

Easy Way to Remember

Easy way to remember Molar Mass of Bromopropane

Molar Mass of Bromopropane: count atoms, multiply masses, and add totals.
Write each element in a table so you do not miss subscripts.
Keep 2-3 decimals during steps, then round only at the end.

Sample Reactions

Type	Reaction
Synthesis	₂H₂ + O₂ → ₂H₂O
Combustion	CH₄ + ₂O₂ → CO₂ + ₂H₂O

Do You Know?

– Bromopropane contains 3 element types: C, H, Br.

– Br contributes the largest share of this compound's total molar mass.

– In C₃H₇Br, H appears with the highest atom count.

– Its molar mass is 122.99 g/mol, which is used directly in gram-to-mole conversions.

– A common reaction for Bromopropane is synthesis (₂H₂ + O₂ → ₂H₂O).

Why This Compound Matters

Bromopropane matters in organic chemistry, especially for fuel, solvent, or carbon-chain analysis.

Its formula pattern helps students practice molecular composition and yield calculation methods.

Similar calculations can be compared with Bromomethane (C₁H₃Br) and Bromoethane (C₂H₅Br).

Where This Is Used

Competitive exams and school chemistry tests.
Lab work when preparing measured solutions.
Real-world manufacturing and quality checks.

Common Mistakes When Calculating This

Skipping subscripts in C₃H₇Br and miscounting atoms.
Rounding atomic masses too early before finishing all multiplication steps.
Mixing up Br element contribution with total molar mass.
Reporting a value without units; final answer should be in g/mol for Bromopropane.

Quick Revision

Formula: C₃H₇Br

Molar Mass: 122.99 g/mol

Key takeaway: count atoms accurately, multiply by atomic masses, and sum only at the end.

Formula Explanation

C₃H₇Br contains Carbon (C) (3), Hydrogen (H) (7), Bromine (Br) (1). Add each element contribution to get total molar mass.

Molar Mass = Sum (atomic mass of each element x atom count)

FAQ

What is the molar mass of C3H7Br?

The molar mass of C3H7Br is 122.99 g/mol based on atomic masses and atom counts.

How do I calculate C3H7Br molar mass quickly?

Count atoms in C3H7Br, multiply each by atomic mass, then add every contribution.

Where is C3H7Br molar mass used?

It is used in lab measurements, exam stoichiometry questions, and mole-to-gram conversions.

How do I convert between grams and moles for C3H7Br?

Use moles = mass (g) / molar mass. With 122.99 g/mol, divide grams by 122.99 to get moles.

Does rounding affect my final C3H7Br answer?

Keep extra digits while multiplying, then round the final molar mass to match your course rules (commonly 2 decimal places).

Conclusion

Molar Mass of Bromopropane and Molar Mass of C₃H₇Br are now easy to revise with this structured page. You can use this method in exams, lab reports, and daily chemistry practice.

Whenever you want to branch out, return through molar mass page for the full molar mass toolkit.

Molar Mass of Bromopropane (C3H7Br)