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Molar Mass Lab/Molar mass for C1H3Br
Organic

Molar Mass of Bromomethane (C1H3Br)

Molar Mass of Bromomethane is helpful for yield calculations and formula checks in carbon-chain reaction questions. Molar Mass of C₁H₃Br is 94.94 g/mol, based on 3 element types, with Br contributing the largest share.

For fast checks, use the molar mass calculator, verify element values in the periodic table, or explore more molar mass.

Molar Mass of Bromomethane is:

94.94 g/mol

Molar Mass of C₁H₃Br equals 94.94 g/mol, so 94.94 grams is one mole.

Element Breakdown Table

ElementCountAtomic massCalculationContribution
Carbon (C)112.011 x 12.0112.01 g/mol
Hydrogen (H)31.013 x 1.013.02 g/mol
Bromine (Br)179.901 x 79.9079.90 g/mol
Final molar mass
12.010 + 3.020 + 79.900
94.94 g/mol

Computing Molar Mass of Bromomethane Step by Step

Molar Mass of Bromomethane: Step-by-Step Calculation

1. Identify Element Counts

Read C1H3Br and list how many atoms of each element are present:

  1. 1 atom of Carbon (C)
  2. 3 atoms of Hydrogen (H)
  3. 1 atom of Bromine (Br)

2. Determine Atomic Masses

Look up each element mass from the periodic table:

  1. Carbon (C) ~= 12.011 g/mol
  2. Hydrogen (H) ~= 1.008 g/mol
  3. Bromine (Br) ~= 79.904 g/mol

3. Multiply Atomic Mass by Quantity

Multiply atom count by atomic mass for each element:

  • Carbon (C): 1 x 12.011 = 12.010 g/mol
  • Hydrogen (H): 3 x 1.008 = 3.020 g/mol
  • Bromine (Br): 1 x 79.904 = 79.900 g/mol

4. Sum Total Molar Mass

Add all contributions to get the final molar mass in g/mol.

Molar Mass = (1 x 12.011 + 3 x 1.008 + 1 x 79.904)

Molar Mass = 12.010 + 3.020 + 79.900

Molar Mass = 94.940 g/mol

Final rounded value shown on this page: 94.94 g/mol.

Visual Calculation Chart

ElementCountMassCount x massContribution
Carbon (C)112.0111 x 12.011= 12.010
Hydrogen (H)31.0083 x 1.008= 3.020
Bromine (Br)179.9041 x 79.904= 79.900
Final molar mass
12.010 + 3.020 + 79.900
= 94.940

Easy Way to Remember

Easy way to remember Molar Mass of Bromomethane

  • Molar Mass of Bromomethane: count atoms, multiply masses, and add totals.
  • Write each element in a table so you do not miss subscripts.
  • Keep 2-3 decimals during steps, then round only at the end.

Sample Reactions

TypeReaction
Synthesis₂H₂ + O₂ → ₂H₂O
CombustionCH₄ + ₂O₂ → CO₂ + ₂H₂O

Do You Know?

Bromomethane contains 3 element types: C, H, Br.

Br contributes the largest share of this compound's total molar mass.

In C₁H₃Br, H appears with the highest atom count.

Its molar mass is 94.94 g/mol, which is used directly in gram-to-mole conversions.

A common reaction for Bromomethane is synthesis (₂H₂ + O₂ → ₂H₂O).

Why This Compound Matters

Bromomethane matters in organic chemistry, especially for fuel, solvent, or carbon-chain analysis.

Its formula pattern helps students practice molecular composition and yield calculation methods.

Similar calculations can be compared with Bromoethane (C2H5Br) and Bromopropane (C3H7Br).

Where This Is Used

  • Competitive exams and school chemistry tests.
  • Lab work when preparing measured solutions.
  • Real-world manufacturing and quality checks.

Common Mistakes When Calculating This

  • Skipping subscripts in C₁H₃Br and miscounting atoms.
  • Rounding atomic masses too early before finishing all multiplication steps.
  • Mixing up Br element contribution with total molar mass.
  • Reporting a value without units; final answer should be in g/mol for Bromomethane.

Quick Revision

Formula: C1H3Br

Molar Mass: 94.94 g/mol

Key takeaway: count atoms accurately, multiply by atomic masses, and sum only at the end.

Formula Explanation

C1H3Br contains Carbon (C) (1), Hydrogen (H) (3), Bromine (Br) (1). Add each element contribution to get total molar mass.

Molar Mass = Sum (atomic mass of each element x atom count)

Keep molar mass calculations open while practicing so your totals match the same method shown here.

FAQ

The molar mass of C1H3Br is 94.94 g/mol based on atomic masses and atom counts.

Conclusion

Molar Mass of Bromomethane and Molar Mass of C₁H₃Br are now easy to revise with this structured page. You can use this method in exams, lab reports, and daily chemistry practice.